Question

A platinum sphere with radius 0.0165 m is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14 × 10 4 kg/m3 and 1.36 × 10 4 kg/m3, respectively.

Answer 1

Weight = 3.924 N

Bouyant force = 2.5N

Apperent weight= 1.424N

Step-by-step explanation:

Radius of the sphere = 0.0165 m

Volume of sphere = (4πr³)/3

Volume = 4.189*(4.49*10^-6)

Volume = 1.88*10^-5

For the weight.

Mass = density* volume

Mass = 2.14*10^4 *(1.88*10^5)

Mass = 0.4 kg.

Weight = mass * acceleration due to gravity

Weight = 0.4*9.81

Weight = 3.924 N

For the buoyant force Fb

Fb = volume * density of fluid* acceleration

Fb = (1.88*10^5)*1.36 × 10^ 4*9.81

Fb = 2.5N

For Apperent weight

True weight - buoyant force = Apperent weight.

3.924- 2.5N= 1.424N