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A .4Kg hula-hoop is rolled down a hill. It has a diameter of 1.2m. The hula-hoop completes 3.4 rotations every 2.8 seconds. What is the linear velocity of the hoop as it comes down the hill?
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A .4Kg hula-hoop is rolled down a hill. It has a diameter of 1.2m. The hula-hoop completes 3.4 rotations every 2.8 seconds. What is the linear velocity of the hoop as it comes down the hill?

User RPiAwesomeness
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5.3k points

1 Answer

8 votes

4.58m/s

Step-by-step explanation:

V= displacement/time

circumference=2(pi)r

displacement= (2)(pi)(.6)(3.4)=12.8176

V= 12.8176/2.8

V=4.58 m/s

User Anthonyv
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4.9k points
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