Answer:
The first 3 terms are 2, 7, 22.
Explanation:
The n is the sequence number of the term: f(1) means the first term.
The second term
f(2) = 3f(n - 1) + 1 We make n = 2:
= 3f(2-1) + 1
= 3f(1) + 1 f(1) = 2 so:
= 3*2 + 1
= 7.
3rd term f(3)
= 3f(3 - 1) + 1
= 3f(2) + 1
= 3(7) + 1
= 22.