How do you find the y-intercept for x = 2y2 + 3y + 1

Question

asked Nov 22, 2021 99.0k views

1 Answer

Marek Vitek · Answer 1 · 2021-11-26T19:40:09+0000

The y intercept is when x=0. That's solving the quadratic

0 = 2y² + 3y + 1 = (2y + 1)(y + 1)

y = -1 or 2y+1=0 so y=-1/2

Two y intercepts, (0,-1) and (0,-1/2)

Answer: -1 and -1/2