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How do you find the y-intercept for x = 2y2 + 3y + 1

1 Answer

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The y intercept is when x=0. That's solving the quadratic

0 = 2y² + 3y + 1 = (2y + 1)(y + 1)

y = -1 or 2y+1=0 so y=-1/2

Two y intercepts, (0,-1) and (0,-1/2)

Answer: -1 and -1/2

User Marek Vitek
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