Question

A chemist is using a solution of hno3 that has a ph of 3.75. what is [h ] for the solution?

Answer 1

`\text{pH} = -\log[H^(+)]\\\\\implies \log[H^(+)] = -\text{pH}\\\\\implies [H^(+)] = 10^{-\text{pH}}}\\\\\implies [H^(+)] =10^(-3.75)=0.00017~M`