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Please Help Fast Algebra 1

Please Help Fast Algebra 1-example-1

2 Answers

4 votes

Answer:

d.

Explanation:

B = ⅗(A - 10)

B = ⅗A - 6

⅗A = B + 6

A = (5/3)(B + 6)

A = (5B + 30)/3

User Miyako
by
8.8k points
2 votes

Answer:

D

Explanation:

First, we need to "undo" the 3/5 fraction by dividing both sides of the equation by 3/5. This is basically the same as multiplying both sides by 3/5's reciprocal, 5/3:


(5)/(3) *B=A-10

Now, we just add 10 to both sides to "undo" the subtraction part:


A=(5)/(3) B+10

We see that all the answer choices are fractions, so we need to find a common denominator for the term (5/3)B and the term 10; we can just use 3 as a denominator. To make 10 have a denominator of 3, we can write 10 as
(10)/(1) and multiply the numerator and denominator by 3:
(10*3)/(1*3)=(30)/(3) . Now, we replace 10 with 30/3:

A =
(5B+30)/(3)

Thus, the answer is D.

Hope this helps!

User Wun
by
8.4k points

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