Question

NASA launches a rocket at

t
=
0
seconds. Its height, in meters above sea-level, as a function of time is given by
h
=
−
4.9
t
2
+
211
t
+
94
.

Answer 1

the height is : 2365.48 m

Explanation:

hello :

h(t) = − 4.9 t 2 + 211 t + 94 .

the vertex of this parabola is : (-b/2a , h(-b/2a) when : a= -4.9 and b=211

-b/2a = -(211)/2(-4.9) = 21.53

h(21.53) = -4.9(21.53)²+211(21.53)+94 = 2365.48 m