Question

What is the solution of log2 (3x-7) =3

Answer 1

The Solution X = 5.

Answer 2

x = 5

Explanation:

because the log is base 2 you can remove the log by raing 2 to the power of each side:

`2^(log2 (3x-7)) = 2^(3)`

the 2 and log2 cancel leaving:

`3x-7 = 2^(3)`

this means we can now solve through simple algebra:

`3x-7 = 8\\3x = 8 + 7\\3x = 15\\3x/3 =15/3\\x = 5`