Question

What is the sine ratio for ∠C?

Question 1 options:

13/12


12/13


5/12


13/5


12/5

What is the cos ratio for ∠C?

Question 2 options:

8/6


8/10


6/10


6/8


10/8

Answer 1

B & C

Explanation:

1.

`sin C = (AB)/(AC) = (12)/(13)`

2.

`cosC=(BC)/(AC) = (6)/(10)`

Answer 2

1. 12/13

2. 6/10

Explanation:

SinC = opposite/hypotenuse

sinC = AB/AC

sinC = 12/13

cosC = adjacent/hypotenuse

cosC = BC/AC

cosC = 6/10 = 3/5