Question

Write an equation that is parallel to y =
1/2x + 2 and goes through the point (2,-3)

Answer 1

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

`y=(1)/(2) x+2` The slope is 2, so the parallel line's slope is also 2.

Now that you know the slope, substitute/plug it into the equation:

y = mx + b

`y=(1)/(2) x+b` To find b, plug in the point (2, -3) into the equation, then isolate/get the variable "b" by itself

`-3=(1)/(2)(2)+b`

-3 = 1 + b Subtract 1 on both sides to get "b" by itself

-3 - 1 = 1 - 1 + b

-4 = b

`y=(1)/(2) x-4`

Answer 2

All you need to do is change the point st which the line crosses the y-axis. 1/2x + will work.