Question

A 500 g bar of copper (c = 387 P/kgoC) at 20.0 oC has 10,050 J of heat removed

from it. What is its final temperature?

Answer 1

The final temperature is 71.94 °C

Step-by-step explanation:

Step 1: Data given

Mass of the copper bar = 500 grams

The specific heat of copper = 387 J/kg°C = 0.387 J/g°C

The initial temperature = 20.0 °C

Heat removed = 10050 J

Step 2: Calculate the final temperature

Q = m*c * ΔT

⇒with Q = the heat removed = 10050 J

⇒with m = the mass of the barr of copper = 500 grams

⇒with c= the specific heat of copper = 0.387 J/g°C

⇒with ΔT = the change of temperature = T2 -T1

10050 = 500 * 0.387 * ΔT

ΔT = 10050 / (500*0.387)

ΔT = 51.94 °C

Step 3: Calculate the final temperature

ΔT = T2 - T1

⇒with ΔT = the change of temperature = 51.94 °C

⇒with T2 = the final temperature = TO BE DETERMINED

⇒with T1 = the initial temperature = 20.0 °C

51.94 °C = T2 - 20.0°C

T2 = 51.94 °C + 20.0 °C

T2 = 71.94 °C

The final temperature is 71.94 °C

Answer 2

T final = 71.5°C

Step-by-step explanation:

• Q= mCΔT

∴ Q = 10050 J

∴ C copper 20°C = 387 P/Kg°C ≅ 390.268 J/KgK

∴ m copper ? 500 g = 0.500 Kg

∴ T1 = 20°C ≅ 293 K

∴ T2 = ?

⇒ ΔT = T2 - T1 = Q / m C = (10050 J) / ((0.500 Kg)(390.268 J/KgK))

⇒ T2 - 293 K = 51.503 K

⇒ T2 = 293 K + 51.503 K

⇒ T2 = 344.503 K ≅ 71.503°C