Question

The rectangular plates in a parallel-plate capacitor are 0.063 m × 5.4 m. A distance of 3.5 × 10–5 m separates the plates. The plates are separated by a dielectric made of Teflon, which has a dielectric constant of 2.1. What is the capacitance of the capacitor?

Answer 1

0.18 µF

Step-by-step explanation:

right on ed2020

Answer 2

capacitance of the capacitor = 0.18 μ F

Step-by-step explanation:

Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²

distance between the plate d = 3.5 × 10–5 m

dielectric value for Teflon K = 2.1

capacitance of capacitor = ?

Formula for capacitance of parallel plate is as follows ,

`C= (K\epsilon_0 A)/(d)` (Where
`\epsilon_0 = 8.82 * 10^-12\ (F)/(m)` )

putting the values in the equation,

C =
`(2.1*8.82*10^-12*0.3402 )/(3.5*10^-5)`
`=0.18* 10^-6` =0.18 μ F