Question

An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally througha distance of 6.00 m along a frictionless surface. What is the change in the kinetic energy of thisobject?

Answer 1

The change in the kinetic energy is 600 J

Step-by-step explanation:

According the work energy expression, the change of kinetic energy is equal to the work done, the equation is:

`deltaE_(k) =W=Fs`

Where

F = force = 100 N

s = distance = 6 m

Replacing:

`deltaE_(k) =100*6=600J`

Answer 2

Δ K.E = 600 J

Step-by-step explanation:

Given that:

the mass of the object = 10.0 kg

Force = 100 N

distance = 6.00 m

what is the change in kinetic energy of this object = Δ K.E

The expression for the change in the kinetic can be illustrated as follows:

Δ K.E = W

where W is the workdone on the object and is given by the formula :

W = F × d

So;

Δ K.E = F × d

Δ K.E = (100 N × 6.00 m)

Δ K.E = 600 N.m

Δ K.E = 600 J

Therefore, the change in the kinetic energy of this object = 600 J