Question

A driven RLC circuit is being driven by an AC emf source with a maximum current of 2.75 A and maximum voltage of 150 V. The current leads the emf of the generator by 0.850 rad. A) What is the impedance of the circuit? B) What is the resistance of the circuit? C) Is the circuit predominantly inductive, or capacitive?

Answer 1

(a). Z = 54.54 ohm

(b). R = 36 ohm

(c). The circuit will be Capacitive.

Step-by-step explanation:

Given data

I = 2.75 A

Voltage = 150 V

`\phi = 0.85` rad = 48.72°

(a). Impedance of the circuit is given by

`Z = (V)/(I)`

`Z = (150)/(2.75)`

Z = 54.54 ohm

(b). We know that resistance of the circuit is given by

`R = \frac{Z}{\sqrt{1 + \tan^(2)\phi } }`

Put the values of Z &
`\phi` in above formula we get

`R = \frac{54.54}{\sqrt{1 + \tan^(2) ( \ 48.72) } }`

R = 36 ohm

(c). Since the phase angle is negative so the circuit will be Capacitive.