Question

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is 42:1. The primary coil is plugged into a standard 120-V outlet. The current in the secondary coil is 2.0 x 10-3 A. Find the power consumed by the air filter.

Answer 1

The power consumed by air filter is 10.08 W

Step-by-step explanation:

Given:

Primary voltage
`V_(p) = 120` V

Current in secondary coil
`I_(s) = 2 * 10^(-3)` A

Turn ratio
`(N_(s) )/(N_(p) ) = (42)/(1)`

For finding power consumed by filter,

`P = V_(p) I_(p)`

We know that the relation between current and number of turns,

`(I_(s) )/(I_(p) ) = (N_(p) )/(N_(s) )`

`P = V_(p) I_(s) (N_(s) )/(N_(p) )`

`P = 120 * 2 * 10^(-3) * 42`

`P = 10.08` W

Therefore, the power consumed by air filter is 10.08 W