Question

In a bucket, there are 5 red marbles, 3 blue marbles, and 2 green marbles. A marble is chosen randomly and then put back into the bucket. Then a 2nd marble is chosen. What is the probability that the first marble was red and the second marble was green

Answer 1

Explanation:

Answer 2

The required probability is
`(1)/(10)`.

Explanation:

Probability:

The ratio of the favorable outcomes to the all possible outcomes.

Given that, in a bucket, there are 5 marbles red in color, 3 marbles blue in color and 2 marbles green in color.

Total number of marbles are = 5+3+2= 10

The probability that first marble was red

`=\frac{\textrm{Number of red marbles}}{\textrm{Total number of marbles}}`

`=(5)/(10)`

`=\frac12`

The probability that second marble was green is

`=\frac{\textrm{Number of green marbles}}{\textrm{Total number of marbles}}`

`=(2)/(10)`

`=\frac15`

The required probability is

`=\frac12 * \frac15`

`=\frac1{10}`