Question

An orthogonal cutting operation is being carried out under the following conditions: depth of cut = 0.1 mm, width of cut = 5 mm, chip thickness = 0.2 mm, cutting speed = 1.5 m/s, rake angle = 15o, cutting force = 400 N, and thrust force = 200 N. Calculate the Material Removal Rate (MRR) during cutting.

Answer 1

MMR = 750 mm^3 /s

Step-by-step explanation:

Given:-

- depth of cut, d = 0.1 mm

- cutting speed, v = 1.5 m/s

- chip thickness, tc = 0.2 mm

- width of cut, w = 5 mm

Find:-

Calculate the Material Removal Rate (MRR) during cutting.

Solution:-

- The amount of material removed per second is given by the following relation, incorporating the speed at which tool moves (cutting speed), the depth of cut and the width of cut:

MRR = v*w*d

= (1.5)*(0.005)*(0.0001)*1000^3

= 750 mm^3 /s