Question

Solve the following please:

Answer 1

Answer: 161

[3×2^5+13×(−2)]+7[8−(4−9)]

Calculate 2 to the power of 5 and get 32.

3×32+13(−2)+7(8−(4−9))

Multiply 3 and 32 to get 96.

96+13(−2)+7(8−(4−9))

Multiply 13 and −2 to get −26.

96−26+7(8−(4−9))

Subtract 26 from 96 to get 70.

70+7(8−(4−9))

Subtract 9 from 4 to get −5.

70+7(8−(−5))

The opposite of −5 is 5.

70+7(8+5)

Add 8 and 5 to get 13.

70+7×13

Multiply 7 and 13 to get 91.

70+91

Add 70 and 91 to get 161.

161

Answer 2

Explanation:

Use PEDMAS

[3 *2⁵ + 13*(-2) ] + 7[8-(4-9) ] = [3*2⁵ + 13*(-2)] +7[ 8 - (-5) ]

{calulate the inner most parentesis (4- 9 = -5)}

= [3*32 + 13*(-2) ] + 7* [ 8+5]

{Find the exponent 2⁵ = 32}

= [ 96 + (-26) ] + 7* 13

{Here 3 & 32 aree multiplied & 13 and (-2) are multiplied and 8 is added to 5}

= 70 + 91

= 161