Answer: 12Ω
Step-by-step explanation:
Since there are resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2 + R3
Given that,
R1 = 3Ω
R2 = 4Ω
R3 = 5Ω
Rtotal = 3Ω + 4Ω + 5Ω
Rtotal = 12Ω (The unit of resistance is ohms, and ohms symbol is Ω)
Thus, the total resistance of the series circuit is 12Ω