Question

A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit is 1.30 W. Assuming that the voltage remains constant, how much power is dissipated when the variable resistor is set to 532Ω? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

Answer 1

Power dissipated in resistor 532 ohm is 0.503 watt

Step-by-step explanation:

We have given in first case resistance
`R_1=206ohm`

Power dissipated in this resistance is
`P_1=1.30watt`

Power dissipated in the resistor is equal to
`P=\frac{v_(rms)}^2{R}`

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that
`(P_1)/(P_2)=(R_2)/(R_1)`

`(1.3)/(P_2)=(532)/(206)`

`P_2=0.503watt`

So power dissipated in resistor 532 ohm is 0.503 watt