Question

A gas has a volume of 1,400 milliliters at a temperature of 20. K and a pressure of 1.0 atm. What will be the new volume when the temperature is changed to 40. K and the pressure is changed to 0.50 atm

Answer 1

Answer : The new volume of will be, 5600 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=1.0atm\\V_1=1400mL\\T_1=20K\\P_2=0.50atm\\V_2=?\\T_2=40K`

Now put all the given values in above equation, we get:

`(1.0atm* 1400mL)/(20K)=(0.50atm* V_2)/(40K)`

`V_2=5600mL`

Therefore, the new volume of will be, 5600 mL