Question

Section BreakProblem 08.048 2.value: 5.00 pointsRequired information Problem 08.048.b Compute the expected error. The expected error is _____%. (Round the final answer to the nearest whole number.)

Answer 1

a) 19 or select the closest answer

b) 5%

Step-by-step explanation:

a)

from the voltage divide rule

`V_(in) = V_0 * (R_2)/(R_2 + R_f)`

`(V_0)/(V_(in)) = (R_2 + R_f)/(R_2) => 1 + (R_f)/(R_2) = 20`

`(R_f)/(R_2) = 19`

Select the nearest answer

b)

obtained gain =
`(V_0)/(V_(in)) = 1 + (36)/(2) = 19`

Expected gain =
`(V_0)/(V_(in)) = 20`

∴ error = |
`(19 - 20)/(20)`| × 100

= 1/20 × 100

= 5%