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A three-point bending test is performed on a glass specimen having a rectangular cross section of height d 5 mm (0.2 in.) and width b 10 mm (0.4 in.); the distance between support points is 45 mm (1.75 in.). Compute the flexural strength if the load at fracture is 290 N (65 lb

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Answer:

The flexural strength of a specimen is = 78.3 M pa

Step-by-step explanation:

Given data

Height = depth = 5 mm

Width = 10 mm

Length L = 45 mm

Load = 290 N

The flexural strength of a specimen is given by


\sigma = (3 F L)/(2 bd^(2) )


\sigma = (3(290)(45))/(2 (10)(5)^(2) )


\sigma = 78.3 M pa

Therefore the flexural strength of a specimen is = 78.3 M pa

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