Answer:
The flexural strength of a specimen is = 78.3 M pa
Step-by-step explanation:
Given data
Height = depth = 5 mm
Width = 10 mm
Length L = 45 mm
Load = 290 N
The flexural strength of a specimen is given by
![\sigma = (3 F L)/(2 bd^(2) )](https://img.qammunity.org/2021/formulas/engineering/college/qiaiy2za5n2ob6kvwfisyt3qwyb15cjjwt.png)
![\sigma = (3(290)(45))/(2 (10)(5)^(2) )](https://img.qammunity.org/2021/formulas/engineering/college/rl2bwckf8chh6dr3ssxx00mpzfcknh2jfl.png)
78.3 M pa
Therefore the flexural strength of a specimen is = 78.3 M pa