Question

If 1,490 compacted cubic yards of in-place soil is required for a project, how many loads of import will be required? The import material has a swell of 14 percent and shrinkage of 95 percent. The trucks can haul 12 loose cubic yards.

Answer 1

The loads that will be required are 149

Step-by-step explanation:

The required bank cubic yard is equal to:

`required-bank-cubic-yard=(required-in-place-cubic-yard)/(shrinkage) =(1490)/(0.95) =1568.42bcy`

The volume of the material is equal to:

`loose-cubic-yard=required-bank-cubic-yard(1+swell-percentage)=1568.42(1+0.14)=1787.99lcy`

The number of truck loads is equal to:

`loads=(lcy-of-haul)/(lcy-per-load) =(1787.99)/(12) =148.99=149loads`

Answer 2

149 loads of import will be required for the project.

Step-by-step explanation:

bank cubic yards = bcy

Loose cubic yards = lcy

Calculate for the required bank cubic yards.

Required bank cubic yards = required in place cubic yards/shrinkage

Substitute

required in place cubic yards = 1,490 ccy

shrinkage percentage = 95% = 0.95

Required bank cubic yards = 1,490/0.95 = 1,568.42 bcy

Determine the volume of the material to be transported

Loose cubic yards = bank cubic yards * (1 + swell percentage)

swell percentage = 14% = 0.14

Loose cubic yards = 1,568.42*(1+0.14) = 1,788 lcy

loads of import that will be required = Loose cubic yards/truck haul capacity

loads of import that will be required = 1,788/12 = 149 load