44.2k views
4 votes
Bonnie and Clyde are sliding a 315 kg bank safe across the floor to their getaway car. The safe slides with a constant speed if Clyde pushes from behind with 381 N of force while Bonnie pulls forward on a rope with 363 N of force.

What is the safe's coefficient of kinetic friction on the bank floor?

1 Answer

5 votes

Answer:

The safe's coefficient of kinetic friction on the bank floor is 0.24

Step-by-step explanation:

Given;

mass of bank safe, m = 315 kg

force applied by Clyde, Fc = 381 N

force applied by Bonnie, Fb = 363 N

Total horizontal force on the safe = 381 N + 363 N

Total horizontal force on the safe = 744 N

Since the safe slides with a constant speed, then the net force on the safe will zero;

Hence perpendicular force on the safe normal to the floor = horizontal force acting of the safe;

Rμk = 744 N

mgμk = 744 N

(315 x 9.8) μk = 744 N

(3087) μk = 744

μk = 744/3087

μk = 0.24

Therefore, the safe's coefficient of kinetic friction on the bank floor is 0.24

User Rui Botelho
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.