44.2k views
4 votes
Bonnie and Clyde are sliding a 315 kg bank safe across the floor to their getaway car. The safe slides with a constant speed if Clyde pushes from behind with 381 N of force while Bonnie pulls forward on a rope with 363 N of force.

What is the safe's coefficient of kinetic friction on the bank floor?

1 Answer

5 votes

Answer:

The safe's coefficient of kinetic friction on the bank floor is 0.24

Step-by-step explanation:

Given;

mass of bank safe, m = 315 kg

force applied by Clyde, Fc = 381 N

force applied by Bonnie, Fb = 363 N

Total horizontal force on the safe = 381 N + 363 N

Total horizontal force on the safe = 744 N

Since the safe slides with a constant speed, then the net force on the safe will zero;

Hence perpendicular force on the safe normal to the floor = horizontal force acting of the safe;

Rμk = 744 N

mgμk = 744 N

(315 x 9.8) μk = 744 N

(3087) μk = 744

μk = 744/3087

μk = 0.24

Therefore, the safe's coefficient of kinetic friction on the bank floor is 0.24

User Rui Botelho
by
5.4k points