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the weekly mean income of a group of executives is $1,000 and the standard deviation of this group is $100. the distribution is normal. what percent of the executives have an income of $925 or less? group of answer choices

User Nesteant
by
5.6k points

1 Answer

5 votes

Answer:

Approximately 23
\% percent of the executives have an income of $925 or less

Explanation:

Given -

Mean income
\boldsymbol{(\\u)} = $1,000

Standard deviation
\boldsymbol{(\sigma )} = $100

Let X be the income of group of executives

what percent of the executives have an income of $925 or less =


P(X\leq 925 ) =
P((X - \\u )/(\sigma)\leq (925 - 1000))/(100))

=
P(Z\leq (-75)/(100) ) Put [
\boldsymbol{Z = (X - \\u )/(\sigma)} ]

=
P(Z\leq -0.75) Using Z table

= .2266

=
22.66\%

=
23%
\% (Approximately)

User BugliL
by
5.2k points
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