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Find the distance from point (2,6) to point (8,3) to the nearest tenth of a unit.

User Cox
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For this case we must find the distance between two points:


(x_ {1}, y_ {1}): (2,6)\\(x_ {2}, y_ {2}) :( 8,3)

By definition, the distance between two points is given by:


d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}\\d = \sqrt {(8-2) ^ 2 + (3-6) ^ 2}\\d = \sqrt {(6) ^ 2 + (- 3) ^ 2}\\d = \sqrt {36 + 9}\\d = \sqrt {45}\\d = 3 \sqrt {5}\\


d = 6.71

Answer:

The distance is 6.71 units

User EdmCoff
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