Question

Find the distance from point (2,6) to point (8,3) to the nearest tenth of a unit.

Answer 1

For this case we must find the distance between two points:

`(x_ {1}, y_ {1}): (2,6)\\(x_ {2}, y_ {2}) :( 8,3)`

By definition, the distance between two points is given by:

`d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}\\d = \sqrt {(8-2) ^ 2 + (3-6) ^ 2}\\d = \sqrt {(6) ^ 2 + (- 3) ^ 2}\\d = \sqrt {36 + 9}\\d = \sqrt {45}\\d = 3 \sqrt {5}\\`

`d = 6.71`

Answer:

The distance is 6.71 units