Answer:
The number of lessons the member and the non member would have to take so the cost for each to be the same = 11 lessons.
Explanation:
Here we have an optimization problem, therefore
Let the number of lessons the members have to take be X and the number of lessons the non members have to take be Y
We have; when Y = X then
55 + 25×Y = 30×Y
55 = 5×Y
Y = 11
The number of lessons the member and the non member would have to take so the cost for each to be the same = 11 lessons.