Answer:
Area of square pyramid is
.
Explanation:
Diagram of the given scenario is shown below,
Given that,
The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is
. The side of the square is
and The height of each triangle is
.
So, Area of Square shape =
![154 \ m^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/h2gddjf3v4izo3va5zc9x3qe4smva235yd.png)
Side of square =
![230 \ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/r7sbkxmm751ei7kq4v2solzmisyk2h9gj0.png)
Height of each triangle =
![187 \ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/248bl64t6zr7bxtzhtefy1clj6q50bwrmi.png)
Finding the Height of triangular shape which is here known as slant height.
In Δ ABO, applying Right angle pythagorean Theorem,
Base
=
![(230)/(2) = 115\ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/e0xrd4fflvjzhaohs78d0yig5e8xl750kd.png)
Height
=
![187\ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/v3u4s8yudq96r3z5wp11o05qg1i7s075h6.png)
Now,
∴
![AB^(2) = AO^(2) \ + \ BO^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/s78d9k5cabk2v3pjhx7vqzvu98416yjl5g.png)
⇒
![AB= \sqrt{AO^(2) \ + \ BO^(2) }](https://img.qammunity.org/2021/formulas/mathematics/high-school/wcjtjwcbm6khhxouu785tk6zfig3eocv9u.png)
⇒
![AB= \sqrt{187^(2) \ + \ 115^(2) }](https://img.qammunity.org/2021/formulas/mathematics/high-school/3454x9ff2m5ul1vgmy4byty4nn3ofhq5cx.png)
⇒
![AB= √(34969 \ + \ 13225 )](https://img.qammunity.org/2021/formulas/mathematics/high-school/f3kzc1x659lzqj99hpfop0zg4oqrb8vw3d.png)
⇒
![AB= 219.53 \ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/p9j8mblvmj0zktyn0fimgqln7d9llkqvre.png)
Then,
Area of square pyramid =
![area \ of \ square + \ 4* area \ of \ traiangle](https://img.qammunity.org/2021/formulas/mathematics/high-school/2g7x7gypmybhgj2l4yq00j383lhi0v4ppc.png)
=
=
![230* 230 \ + 2* 219.53* 230](https://img.qammunity.org/2021/formulas/mathematics/high-school/bpah4arj2iwab7xmtwlsdi3lbju8z2hh38.png)
=
![52900 + 100983.8](https://img.qammunity.org/2021/formulas/mathematics/high-school/8j77vmg8zqhcpl1n6pm3t1trqneqemcbd5.png)
=
![153883.8 \ m^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yn6ap75idv31zqxbdkz73lvmns5ps8blc3.png)
Hence, Area of square pyramid is
.