Answer:
![2.84\cdot 10^(-5) y^(-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/wlyuqwoad1qon0y29ub0ufo6yn7svgcmmy.png)
Explanation:
The decay rate of a radioactive isotope (also called activity of the isotope) is given by:
![r=k N](https://img.qammunity.org/2021/formulas/mathematics/high-school/f4czwng12pz77mcqgknzzpuo01cc98b2io.png)
where
r is the decay rate
k is the decay constant
N is the number of nuclei in the radioactive sample
The decay constant of a radioactive isotope is also related to the half-life of the isotope by the formula
![k=(ln2)/(t_(1/2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/nkk7rv3ohm7sczcj3n1bvflk0f8d6n1ufv.png)
where
is the half-life of the isotope, which is the time taken for the sample to halve, compared to its initial amount
In this problem, the half-life of plutioniun-239 is
![t_(1/2)=24,360 y](https://img.qammunity.org/2021/formulas/mathematics/high-school/2gk7azcy2pqekriewni4qknlfhoi0jmna7.png)
Therefore, the k-factor (decay constant) is:
![k=(ln 2)/(24,360)=2.84\cdot 10^(-5) y^(-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/rtvynh8bjoka7ma5ukig5d4eqcnagi9pzk.png)