Question

There are 7 cherries and 3 grapes in a bag. What is the pobability of selecting 2 grapes at random without replacement?

Answer 1

1/15

Explanation:

7+3 = 10 items in the bag

P(grape) = grapes/total

3/10

No replacement

7 cherries 2 grapes = 9 items

P(grape) = grapes/total

2/9

P(grape, no replacement, grape) = 3/10*2/9

=1/15