Question

Calculate the energy absorbed when 6.20 g of aluminum is heated from 10.0°C to 65.0°C if the specific heat of aluminum is 0 .900 J/g°C

Answer 1

The energy absorbed when 6.20 grams of aluminum is heated from 10.0°C to 65.0°C is 306.9 Joules.

Step-by-step explanation:

`Q=mc\Delta T=mc* (T_2-T_1)`

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

`T_1,T_2` : Initial and final temperature of the substance

We have mass of aluminium = m = 6.20 g

Specific heat of aluminium= c = 0.900 J/g°C

Initial and final temperature of the aluminium
`T_1=10.0^oC`

Final temperature of the aluminium =
`T_2=65.0^oC`

Heat absorbed by the aluminium:

`Q=6.20 g* 0.900J/g^oC* (65.0^oC-10.0^oC)=306.9 J`

The energy absorbed when 6.20 grams of aluminum is heated from 10.0°C to 65.0°C is 306.9 Joules.