Compute the distance between (7,-4,9) and (x,y,z). a. (7 + x)2 + (-4 + y)2 + (9 + 2)2 b. (7 - x)2 + (-4 - y)2 + (9 - 2)2 C. d. 7- x) + (-4-y) + (9 -23 (7+ x)2 + (-4+ y)2 + (9+ 2…

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asked Aug 12, 2021 208k views

2 Answers

Juru · Answer 1 · 2021-08-16T14:27:54+0000

Option b:

$\boxed{ d=√((7-x)^2+(-4-y)^2+(9-z)^2)}$

Let two points be:

$P_(1)(x_(1),y_(1),z_(1)) \\ \\ P_(2)(x_(2),y_(2),z_(2))$

The distance formula is defined as:

$d=\sqrt{(x_(1)-x_(2))^2+(y_(1)-y_(2))^2+(z_(1)-z_(2))^2}$

Therefore, if we define:

$P_(1)(7,-4,9) \ and \ P_(2)(x,y,z) \\ \\ \\ Then: \\ \\ d=√((7-x)^2+(-4-y)^2+(9-z)^2)$

Finally, correct option is b