Question

Compute the distance between (7,-4,9) and (x,y,z).

a. (7 + x)2 + (-4 + y)2 + (9 + 2)2
b. (7 - x)2 + (-4 - y)2 + (9 - 2)2
C.
d.
7- x) + (-4-y) + (9 -23
(7+ x)2 + (-4+ y)2 + (9+ 2)2

Answer 1

The Answer is correct, he just has the wrong letter.

Step-by-step explanation:

The correct answer is C

Answer 2

Option b:

`\boxed{ d=√((7-x)^2+(-4-y)^2+(9-z)^2)}`

Step-by-step explanation:

Let two points be:

`P_(1)(x_(1),y_(1),z_(1)) \\ \\ P_(2)(x_(2),y_(2),z_(2))`

The distance formula is defined as:

`d=\sqrt{(x_(1)-x_(2))^2+(y_(1)-y_(2))^2+(z_(1)-z_(2))^2}`

Therefore, if we define:

`P_(1)(7,-4,9) \ and \ P_(2)(x,y,z) \\ \\ \\ Then: \\ \\ d=√((7-x)^2+(-4-y)^2+(9-z)^2)`

Finally, correct option is b