Answer:
The initial angle between the dipole moment and the magnetic field is 47.76⁰
Step-by-step explanation:
Given;
magnitude of dipole moment, μ = 0.0243 J/T
magnitude of magnetic field, B = 57.5 mT
change in kinetic energy, ΔKE = 0.458 mJ
ΔKE = - ΔU
ΔKE = - (U₂ -U₁)
ΔKE = U₁ - U₂
U₁ -U₂ = 0.458 mJ

where;
θ₁ is the initial angle between the dipole moment and the magnetic field
is the final angle which is zero (0) since the dipole moment is aligned with the magnetic field
μB(cos0 - cosθ₁) = 0.458 mJ
Substitute the given values of μ and B
0.0243 x 0.0575 (1 - cosθ₁) = 0.000458
0.00139725 (1 - cosθ₁) = 0.000458
(1 - cosθ₁) = 0.000458 / 0.00139725
(1 - cosθ₁) = 0.327787
cosθ₁ = 1 - 0.327787
cosθ₁ = 0.672213
θ₁ = cos⁻¹ (0.672213)
θ₁ = 47.76⁰
Thus, the initial angle between the dipole moment and the magnetic field is 47.76⁰