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Estimate the size of a crowd at an airshow that occupies a rectangular space with dimensions of 500 feet by 750 feet (to the nearest whole number).

Assume that each person occupies 9 square feet.
A) 10,417 people
B) 20,833 people
C) 41,667 people
D) 83,333 people

User Zeokav
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2 Answers

2 votes

the answer is c.) 41,667 people

User Hoppy
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2 votes

Answer:

C. 41667 people

Explanation:

750 * 500 = 375000 / 9 = 41666.666 = 41667

User Matt Cruikshank
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