Answer:
130 gram of NaN₃should be put into the compartment
Step-by-step explanation:
Given that Ideal volume for an airbag = 50 lit
Pressure = 765 mmHg
we know
![1 atm=760mmHg](https://img.qammunity.org/2021/formulas/chemistry/high-school/me2t4v7yds11cmjihf80yvveggocj6hz0e.png)
∴
![765mmHg =(765)/(760)atm](https://img.qammunity.org/2021/formulas/chemistry/high-school/ux7b1i9uum1w9p5h0m75m08bxbl6d18dvo.png)
Temperature (T) = 29.5°C = (29.5 + 273) = 302.5 K
We know A/c to ideal gas equation
PV = nRT
![n=(PV)/(RT)](https://img.qammunity.org/2021/formulas/engineering/college/ki1yx8lpgcfmh4d9rnxysugq50to01dgw7.png)
Where n= no. of mole
R = universal gas constant = 0.0821 lit. atm. mol⁻¹K⁻¹
![n=((765)/(760) X50)/(0.0821X302.5)=2 mole](https://img.qammunity.org/2021/formulas/chemistry/high-school/r34e699i4ekr9bnn2me2sdggpeypl5myj5.png)
Mass of (NaN₃) = mole x molar mass = 2 x 65 = 130 gram