Question

the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on the surface of its support.?​

Answer 1

your answer is here 180

Step-by-step explanation:

900/2.5 * 2 = 180

Answer 2

The answer is 180 Pa.

Step-by-step explanation:

Given;

Here, weight = thrust = 900 N,

dimensions are 2.5 m × 2 m × 1.2 m

To Find;

• Pressure exerted by the block on the surface of its support.

Formula;

• Pressure = Thrust ÷ Area

We know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.

So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.

Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa

Thus, The pressure exerted by the block on the support is 180 Pa.