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Does the point (1, radical 7) lie on the circle shown? Explain. Yes, the distance from (–2, 4) to (–2, 0) is 4 units. Yes, the distance from (–2, 0) to (1, ) is 4 units. No, the distance from (–2, 0) to (1, ) is not 4 units. No, the distance from (–2, 4) to (1, ) is not 4 units.

2 Answers

2 votes

Answer:

The answer is b

Explanation:

User Cmthakur
by
8.4k points
4 votes

Answer:

Yes,the distance from (-2,0) to
(1,\sqrt 7) is 4 units

Explanation:

We are given that

Center of circle=(-2,0)

Let point P(
1,\sqrt 7)

We have to find that (
1,\sqrt 7) lies on the circle or not.

Distance formula:
√((x_2-x_1)^2+(y_2-y_1)^2)

Using the formula

Distance between Center (-2,0) and (-2,4)=Radius of circle=R


R=√((-2+2)^2+(4-0)^2)


R=√((4)^2)=4units

Distance between (-2,0) and (1,
\sqrt 7)=
√((1+2)^2+(\sqrt 7-0)^2)=4units

Distance between point P(
1,\sqrt 7) and center (-2,0)=Radius of circle

Hence, the point P
(1,\sqrt 7) lies on the circle.

Yes,the distance from (-2,0) to
(1,\sqrt 7) is 4 units

User Shenny
by
8.4k points

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