Question

Does the point (1, radical 7) lie on the circle shown? Explain. Yes, the distance from (–2, 4) to (–2, 0) is 4 units. Yes, the distance from (–2, 0) to (1, ) is 4 units. No, the distance from (–2, 0) to (1, ) is not 4 units. No, the distance from (–2, 4) to (1, ) is not 4 units.

Answer 1

The answer is b

Explanation:

Answer 2

Yes,the distance from (-2,0) to
`(1,\sqrt 7)` is 4 units

Explanation:

We are given that

Center of circle=(-2,0)

Let point P(
`1,\sqrt 7)`

We have to find that (
`1,\sqrt 7)` lies on the circle or not.

Distance formula:
`√((x_2-x_1)^2+(y_2-y_1)^2)`

Using the formula

Distance between Center (-2,0) and (-2,4)=Radius of circle=R

`R=√((-2+2)^2+(4-0)^2)`

`R=√((4)^2)=4`units

Distance between (-2,0) and (1,
`\sqrt 7`)=
`√((1+2)^2+(\sqrt 7-0)^2)=4`units

Distance between point P(
`1,\sqrt 7`) and center (-2,0)=Radius of circle

Hence, the point P
`(1,\sqrt 7)` lies on the circle.

Yes,the distance from (-2,0) to
`(1,\sqrt 7)` is 4 units