Question

What is the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide

Answer 1

`0.25moldm^(-3)`

Step-by-step explanation:

Molarity could be defined as the amount of solute (in moles) dissolved in 1 litre of water to give its solution. It can also be referred to as the concentration of the resulting solution.

The molarity is thus calculated as follows;

`1litre=1dm^(-3)\\hence\\2litres=2dm^(-3)`

`molarity=(0.5mole)/(2dm^(3))\\molarity=0.25moldm^(-3)`

Answer 2

0.25M

Step-by-step explanation:

We can apply the following formula to find molarity ,since the Molarity (M) is the number of moles of solute per liter of solution.

`Molarity=(mol)/(L)`

`mol=0.50mol` of KI(potassium iodide)

`L=2.0liters`

we can substitute the values to find the molarity

`Molarity=(mol)/(L)\\Molarity=(0.50mol)/(2.0liters) \\Molarity=0.25M`

So the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M