A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 pm it was at the point 100, where could it be at 7:20 pm?

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asked Feb 1, 2021 73.6k views

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Jeremy Radcliff · Answer 1 · 2021-02-06T16:54:56+0000

7:15-7:20 is 5 minutes
If every one minute is 11 units then it would be 5x11=55
If it was at point 100 it would now be at point 100+55=155
Answer: point 155
Hope this is correct and helps :)

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A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 pm it was at the point 100, where could it be at 7:20 pm?

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