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Y=x^2+x+5 How many x-intercepts does the graph of this quadratic have?

User Sean Azlin
by
8.7k points

1 Answer

7 votes

Answer:

0

Explanation:

Use discramint formula,


\sqrt{ {b}^(2) - 4ac}

Here a and b is 1

c is 5 so we have


\sqrt{ {1}^(2) - 4(1)(5) }


√(1 - 20)


√( - 19)

Since the number is negative, we have zero x intercepts.

User Madhu Kumar
by
8.0k points

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