Question

Y=x^2+x+5 How many x-intercepts does the graph of this quadratic have?

Answer 1

0

Explanation:

Use discramint formula,

`\sqrt{ {b}^(2) - 4ac}`

Here a and b is 1

c is 5 so we have

`\sqrt{ {1}^(2) - 4(1)(5) }`

`√(1 - 20)`

`√( - 19)`

Since the number is negative, we have zero x intercepts.