Question

The critical resolved shear stress for a metal is 31 MPa. Determine the maximum possible yield strength (in MPa) for a single crystal of this metal that is pulled in tension.

Answer 1

62 MPa

Step-by-step explanation:

We are given that

Critical resolved shear stress for a metal,
`\tau_(crit)=31MPa`

We have to find the maximum possible yield strength for a single crystal of this metal that is pulled in tension.

Yield strength,
`\sigma_(yield)=(\tau_(crit))/(cos\phi cos\gamma)`

Minimum stress is necessary to introduce yielding when
`\phi=\gamma=45^(\circ)`

`\sigma_(yield)=(\tau_(crit))/(cos45cos 45)=2\tau_(crit)`

Substitute the values

`\sigma_(yield)=2* 31=62 MPa`

Hence, the maximum possible yield strength for a single crystal of this metal that is pulled in tension=62 MPa