Question

Date:

Page:-
- 2450 pieces of cubical blocks each of
Side 20cm are required to construct the
wall of 15m long, 40cm width. if
wall has a window of side 2.5m ×
1m And a door of size 2m× 3m. what
is height of evall?​

Answer 1

The height of the wall is 2.7 m.

Step-by-step explanation:

The number of blocks required = 2450. Each cubical block has a side of 20cm(0.2m).

But, volume = length × width × height.

So that,

the volume of each block = (0.2 × 0.2 ×0.2)
`m^(3)`

= 0.008
`m^(3)`

The total volume of the blocks to be used = 2450 × 0.008

= 19.6
`m^(3)`

The window has a measurement of 2.5m ×1m;

its space volume = 2.5m ×1m × 0.4m

= 1.0
`m^(3)`

The door has a measurement of 2m× 3m;

its space volume = 2m× 3m × 0.4m

= 2.4
`m^(3)`

Thus, the window space and door space has a volume = 1.0
`m^(3)` + 2.4
`m^(3)`

= 3.4
`m^(3)`

Total volume of the wall = length × width × height

⇒ The total volume of the blocks - the window space and door space volume = length × width × height

The wall to be constructed has a length of 15m and width 40cm (0.4m).

So that the height could be determined as,

19.6
`m^(3)` - (3.4
`m^(3)`) = 15m × 0.4m × height

16.2
`m^(3)` = 6
`m^(2)` ×height

⇒ height =
`(16.2)/(6)`

height = 2.7 m

Therefore, the height of the wall is 2.7m.